c^2-11c=10

Solution for c^2-11c=10 equation:

c^2-11c=10

We move all terms to the left:

c^2-11c-(10)=0

a = 1; b = -11; c = -10;
Δ = b2-4ac
Δ = -112-4·1·(-10)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{161}}{2*1}=\frac{11-\sqrt{161}}{2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{161}}{2*1}=\frac{11+\sqrt{161}}{2}
$